Find the differential coefficient of tan^-1x with respect to x. - Sarthaks eConnect | Largest Online Education Community
![A new treatise on the elements of the differential and integral calculus . - COS. (f For the area of the segment OMN, we liavo k. = / y-dfl^ 404 INTEGRAL A new treatise on the elements of the differential and integral calculus . - COS. (f For the area of the segment OMN, we liavo k. = / y-dfl^ 404 INTEGRAL](https://c8.alamy.com/comp/2CHBK46/a-new-treatise-on-the-elements-of-the-differential-and-integral-calculus-cos-f-for-the-area-of-the-segment-omn-we-liavo-k-=-y-dfl-404-integral-calculus-which-by-substituting-for-r-its-value-above-becomes2jcos3-l-sin32-2jcos9a-cos-sin-to-effect-this-integration-put-=-ata-n2-cos-d-l-tan3-=-2-czg-stan-9-and-hence-tan2-6-l-tan3-7-t-=-31-tan2-g-1-6-1-tan3-7-the-area-beginning-when-=-0-we-have-7-=-and-con-sequently-a2-tan3-0-u-6-1-tan3-the-entire-area-oml-is-found-by-making-6-=-in-th-2CHBK46.jpg)
A new treatise on the elements of the differential and integral calculus . - COS. (f For the area of the segment OMN, we liavo k. = / y-dfl^ 404 INTEGRAL
![A new treatise on the elements of the differential and integral calculus . - hence ,^^,^ rsin. A^tan. NQ3I = . 7 -{- AT — r COS. Ad Now let the A new treatise on the elements of the differential and integral calculus . - hence ,^^,^ rsin. A^tan. NQ3I = . 7 -{- AT — r COS. Ad Now let the](https://c8.alamy.com/comp/2CHC830/a-new-treatise-on-the-elements-of-the-differential-and-integral-calculus-hence-rsin-atan-nq3i-=-7-at-r-cos-ad-now-let-the-point-q-move-towards-31-the-limiting-position-of-the-secant-q3i-is-the-tangent-3it-and-the-limit-of-the-angle-nqiis-the-angle-f3it-call-this-angle-then-rsin-a-rsin-a-tan-p-z=i-lim-=-hm-r-4-ar-r-cos-a-2sm-f-ar-r-sin-a-zlim-t-jr-sin-ao-ao-a-a-sin-sin-sin-a9-2-the-limit-of-=-1-lim-==-lim-sin-i-0-ao-a-ay-2-ar-7r-do-and-iim-is-donotod-nv-2CHC830.jpg)